b^2+4b+12=

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Solution for b^2+4b+12= equation:


Simplifying
b2 + 4b + 12 = 0

Reorder the terms:
12 + 4b + b2 = 0

Solving
12 + 4b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + 4b + -12 + b2 = 0 + -12

Reorder the terms:
12 + -12 + 4b + b2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 4b + b2 = 0 + -12
4b + b2 = 0 + -12

Combine like terms: 0 + -12 = -12
4b + b2 = -12

The b term is 4b.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4b + 4 + b2 = -12 + 4

Reorder the terms:
4 + 4b + b2 = -12 + 4

Combine like terms: -12 + 4 = -8
4 + 4b + b2 = -8

Factor a perfect square on the left side:
(b + 2)(b + 2) = -8

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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